문제
MYSQL
내가 작성한 정답
select id, case when pr <= 0.25 then 'CRITICAL'
when pr <= 0.5 then 'HIGH'
when pr <= 0.75 then 'MEDIUM'
else 'LOW' end COLONY_NAME
from (select id, percent_rank() over(order by SIZE_OF_COLONY desc) pr
from ECOLI_DATA) o
order by 1;