[SQL문제풀기] 자동차 대여 기록에서 장기/단기 대여 구분하기

문제

MYSQL

내가 작성한 오답

SELECT HISTORY_ID,CAR_ID,DATE_FORMAT(START_DATE,'%Y-%m-%d') START_DATE,
        DATE_FORMAT(END_DATE,'%Y-%m-%d') END_DATE,
        CASE WHEN END_DATE-START_DATE+1 >= 30 THEN '장기 대여'
            ELSE '단기 대여' END RENT_TYPE
FROM CAR_RENTAL_COMPANY_RENTAL_HISTORY
WHERE DATE_FORMAT(START_DATE,'%y%m') = '2209'
ORDER BY 1 DESC;

내가 작성한 정답

SELECT HISTORY_ID,CAR_ID,DATE_FORMAT(START_DATE,'%Y-%m-%d') START_DATE,
        DATE_FORMAT(END_DATE,'%Y-%m-%d') END_DATE,
        CASE WHEN DATEDIFF(END_DATE,START_DATE)+1 >= 30 THEN '장기 대여'
            ELSE '단기 대여' END RENT_TYPE
FROM CAR_RENTAL_COMPANY_RENTAL_HISTORY
WHERE DATE_FORMAT(START_DATE,'%y%m') = '2209'
ORDER BY 1 DESC;

ORACLE

내가 작성한 정답

SELECT HISTORY_ID, CAR_ID, TO_CHAR(START_DATE, 'YYYY-MM-DD') START_DATE,
        TO_CHAR(END_DATE,'YYYY-MM-DD'),
        CASE WHEN END_DATE-START_DATE+1 >= 30 THEN '장기 대여'
             ELSE '단기 대여' END RENT_TYPE
FROM CAR_RENTAL_COMPANY_RENTAL_HISTORY
WHERE TO_CHAR(START_DATE,'YYMM')='2209'
ORDER BY 1 DESC;