[SQL문제풀기] 가구 판매의 비중이 높았던 날 찾기

silver

Sep 25, 2025

Contents

문제 SQLite

문제

solvesql.com

https://solvesql.com/problems/day-of-furniture/

SQLite

내가 작성한 정답

→ distinct!!로 잘 걸러내야한다


select order_date,
      count(distinct case when category = 'Furniture' then order_id end) furniture,
      round((count(distinct case when category = 'Furniture' then order_id end)*100.00/count(distinct order_id)*1.0),2) furniture_pct
from records
group by order_date 
having count(distinct order_id) >= 10 
  and (count(distinct case when category = 'Furniture' then order_id end)*100.00/count(distinct order_id)*1.0) >= 40
order by 3 desc, 1;