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    SQL문제풀기

    [SQL문제풀기] Friend Requests II: Who Has the Most Friends

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    silver
    Nov 16, 2025
    [SQL문제풀기] Friend Requests II: Who Has the Most Friends
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    문제MySQL

    문제

    Friend Requests II: Who Has the Most Friends - LeetCode
    Can you solve this real interview question? Friend Requests II: Who Has the Most Friends - Table: RequestAccepted +----------------+---------+ | Column Name | Type | +----------------+---------+ | requester_id | int | | accepter_id | int | | accept_date | date | +----------------+---------+ (requester_id, accepter_id) is the primary key (combination of columns with unique values) for this table. This table contains the ID of the user who sent the request, the ID of the user who received the request, and the date when the request was accepted.   Write a solution to find the people who have the most friends and the most friends number. The test cases are generated so that only one person has the most friends. The result format is in the following example.   Example 1: Input: RequestAccepted table: +--------------+-------------+-------------+ | requester_id | accepter_id | accept_date | +--------------+-------------+-------------+ | 1 | 2 | 2016/06/03 | | 1 | 3 | 2016/06/08 | | 2 | 3 | 2016/06/08 | | 3 | 4 | 2016/06/09 | +--------------+-------------+-------------+ Output: +----+-----+ | id | num | +----+-----+ | 3 | 3 | +----+-----+ Explanation: The person with id 3 is a friend of people 1, 2, and 4, so he has three friends in total, which is the most number than any others.   Follow up: In the real world, multiple people could have the same most number of friends. Could you find all these people in this case?
    Friend Requests II: Who Has the Most Friends - LeetCode
    https://leetcode.com/problems/friend-requests-ii-who-has-the-most-friends/description/?envType=study-plan-v2&envId=top-sql-50
    Friend Requests II: Who Has the Most Friends - LeetCode

    MySQL

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    select id, count(*) num from (select requester_id id from RequestAccepted union all select accepter_id id from RequestAccepted) n group by id order by 2 desc limit 1;
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