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    SQL문제풀기

    [SQL문제풀기] 폐쇄할 따릉이 정류소 찾기 2

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    silver
    Mar 14, 2025
    [SQL문제풀기] 폐쇄할 따릉이 정류소 찾기 2
    Contents
    문제SQLite

    문제

    solvesql.com
    solvesql.com
    https://solvesql.com/problems/find-unnecessary-station-2/

    SQLite

    내가 작성한 정답

    : 각 연도의 rent와 return을 컬럼명을 같게하여 union all한 후 sum으로 더했다.
    with tb18 as ( select station_id, sum(cnt) "2018" from (select rent_station_id station_id, count(*) cnt from rental_history where strftime ('%Y%m', rent_at) = '201810' group by rent_station_id union all select return_station_id station_id, count(*) cnt from rental_history where strftime ('%Y%m', return_at) = '201810' group by return_station_id) group by station_id), tb19 as ( select station_id, sum(cnt) "2019" from (select rent_station_id station_id, count(*) cnt from rental_history where strftime ('%Y%m', rent_at) = '201910' group by rent_station_id union all select return_station_id station_id, count(*) cnt from rental_history where strftime ('%Y%m', return_at) = '201910' group by return_station_id) group by station_id) select s.station_id, s.name, s.local, round(b."2019"*10000*0.01/a."2018",2) usage_pct from tb18 a join tb19 b on a.station_id = b.station_id join station s on a.station_id = s.station_id where a."2018"*0.5 >= b."2019"
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