[SQL문제풀기] Salaries Differences

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Nov 26, 2025
[SQL문제풀기] Salaries Differences
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문제MySQL

문제

MySQL

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with a as (select max(e.salary) s from db_employee e join db_dept d on e.department_id = d.id and d.department in ('engineering','marketing') group by e.department_id) select max(s)- min(s) from a;
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